Base | Representation |
---|---|
bin | 11101100011111001010111… |
… | …001100101101110110001111 |
3 | 122001022211212000020000212100 |
4 | 131203321113030231312033 |
5 | 114020041212442014411 |
6 | 1140301454225010143 |
7 | 36245631021614544 |
oct | 3543712714556617 |
9 | 561284760200770 |
10 | 130010123001231 |
11 | 38474a90093950 |
12 | 126b89bb183953 |
13 | 5770b958aa645 |
14 | 24167487bcbcb |
15 | 1006cdd151456 |
hex | 763e5732dd8f |
130010123001231 has 12 divisors (see below), whose sum is σ = 204864436244520. Its totient is φ = 78794013940080.
The previous prime is 130010123001229. The next prime is 130010123001257. The reversal of 130010123001231 is 132100321010031.
130010123001231 is a `hidden beast` number, since 1 + 30 + 0 + 101 + 2 + 300 + 1 + 231 = 666.
It is not a de Polignac number, because 130010123001231 - 21 = 130010123001229 is a prime.
It is a super-2 number, since 2×1300101230012312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130010123001221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 656616782736 + ... + 656616782933.
It is an arithmetic number, because the mean of its divisors is an integer number (17072036353710).
Almost surely, 2130010123001231 is an apocalyptic number.
130010123001231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
130010123001231 is a deficient number, since it is larger than the sum of its proper divisors (74854313243289).
130010123001231 is a wasteful number, since it uses less digits than its factorization.
130010123001231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1313233565686 (or 1313233565683 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 18.
Adding to 130010123001231 its reverse (132100321010031), we get a palindrome (262110444011262).
The spelling of 130010123001231 in words is "one hundred thirty trillion, ten billion, one hundred twenty-three million, one thousand, two hundred thirty-one".
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