Search a number
-
+
13001022021022 = 275591166096303
BaseRepresentation
bin1011110100110000100101…
…0011001001110110011110
31201000212220120121120112221
42331030021103021312132
53201002043114133042
643352330450015554
72511202305546460
oct275141123116636
951025816546487
1013001022021022
11416277aaa4272
12155b827b775ba
13733cb6635899
1432d377a66130
151782be267d67
hexbd3094c9d9e

13001022021022 has 16 divisors (see below), whose sum is σ = 22291452767232. Its totient is φ = 5570869969080.

The previous prime is 13001022020971. The next prime is 13001022021077. The reversal of 13001022021022 is 22012022010031.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 13001022020987 and 13001022021005.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 82969878 + ... + 83126425.

It is an arithmetic number, because the mean of its divisors is an integer number (1393215797952).

Almost surely, 213001022021022 is an apocalyptic number.

13001022021022 is a deficient number, since it is larger than the sum of its proper divisors (9290430746210).

13001022021022 is a wasteful number, since it uses less digits than its factorization.

13001022021022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 166101903.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 13001022021022 its reverse (22012022010031), we get a palindrome (35013044031053).

The spelling of 13001022021022 in words is "thirteen trillion, one billion, twenty-two million, twenty-one thousand, twenty-two".

Divisors: 1 2 7 14 5591 11182 39137 78274 166096303 332192606 1162674121 2325348242 928644430073 1857288860146 6500511010511 13001022021022