13001024131 has 2 divisors, whose sum is σ = 13001024132. Its totient is φ = 13001024130.

The previous prime is 13001024117. The next prime is 13001024149. The reversal of 13001024131 is 13142010031.

13001024131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13001024131 is a prime.

It is a super-2 number, since 2×13001024131² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13001024161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500512065 + 6500512066.

It is an arithmetic number, because the mean of its divisors is an integer number (6500512066).

Almost surely, 2^13001024131 is an apocalyptic number.

13001024131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001024131 is an equidigital number, since it uses as much as digits as its factorization.

13001024131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13001024131 its reverse (13142010031), we get a palindrome (26143034162).

The spelling of 13001024131 in words is "thirteen billion, one million, twenty-four thousand, one hundred thirty-one".