Base | Representation |
---|---|
bin | 11101100011111001100011… |
… | …000011110101110011111111 |
3 | 122001022212100212200021102202 |
4 | 131203321203003311303333 |
5 | 114020042114413014101 |
6 | 1140301530054142115 |
7 | 36245635656235334 |
oct | 3543714303656377 |
9 | 561285325607382 |
10 | 130010322001151 |
11 | 38475082453499 |
12 | 126b8a5595193b |
13 | 5770bc7ba4687 |
14 | 2416766dc098b |
15 | 1006d0085e36b |
hex | 763e630f5cff |
130010322001151 has 2 divisors, whose sum is σ = 130010322001152. Its totient is φ = 130010322001150.
The previous prime is 130010322001141. The next prime is 130010322001223. The reversal of 130010322001151 is 151100223010031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130010322001151 - 210 = 130010322000127 is a prime.
It is a super-2 number, since 2×1300103220011512 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130010322001111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005161000575 + 65005161000576.
It is an arithmetic number, because the mean of its divisors is an integer number (65005161000576).
Almost surely, 2130010322001151 is an apocalyptic number.
130010322001151 is a deficient number, since it is larger than the sum of its proper divisors (1).
130010322001151 is an equidigital number, since it uses as much as digits as its factorization.
130010322001151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 130010322001151 its reverse (151100223010031), we get a palindrome (281110545011182).
The spelling of 130010322001151 in words is "one hundred thirty trillion, ten billion, three hundred twenty-two million, one thousand, one hundred fifty-one".
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