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130010322001223 is a prime number
BaseRepresentation
bin11101100011111001100011…
…000011110101110101000111
3122001022212100212200021112102
4131203321203003311311013
5114020042114413014343
61140301530054142315
736245635656235466
oct3543714303656507
9561285325607472
10130010322001223
1138475082453554
12126b8a5595199b
135770bc7ba4711
142416766dc09dd
151006d0085e3b8
hex763e630f5d47

130010322001223 has 2 divisors, whose sum is σ = 130010322001224. Its totient is φ = 130010322001222.

The previous prime is 130010322001151. The next prime is 130010322001271. The reversal of 130010322001223 is 322100223010031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130010322001223 - 216 = 130010321935687 is a prime.

It is a super-2 number, since 2×1300103220012232 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130010322001195 and 130010322001204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130010322004223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005161000611 + 65005161000612.

It is an arithmetic number, because the mean of its divisors is an integer number (65005161000612).

Almost surely, 2130010322001223 is an apocalyptic number.

130010322001223 is a deficient number, since it is larger than the sum of its proper divisors (1).

130010322001223 is an equidigital number, since it uses as much as digits as its factorization.

130010322001223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 130010322001223 its reverse (322100223010031), we get a palindrome (452110545011254).

The spelling of 130010322001223 in words is "one hundred thirty trillion, ten billion, three hundred twenty-two million, one thousand, two hundred twenty-three".