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13001041322110 = 251300104132211
BaseRepresentation
bin1011110100110000101001…
…1100110010000001111110
31201000212221220221011200001
42331030022130302001332
53201002113034301420
643352332415424514
72511202631605042
oct275141234620176
951025856834601
1013001041322110
11416278a987486
12155b83252513a
13733cba632b4a
1432d37a44c022
151782c0ccbb0a
hexbd30a73207e

13001041322110 has 8 divisors (see below), whose sum is σ = 23401874379816. Its totient is φ = 5200416528840.

The previous prime is 13001041322099. The next prime is 13001041322123. The reversal of 13001041322110 is 1122314010031.

13001041322110 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650052066096 + ... + 650052066115.

It is an arithmetic number, because the mean of its divisors is an integer number (2925234297477).

Almost surely, 213001041322110 is an apocalyptic number.

13001041322110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13001041322110 is a deficient number, since it is larger than the sum of its proper divisors (10400833057706).

13001041322110 is a wasteful number, since it uses less digits than its factorization.

13001041322110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1300104132218.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13001041322110 its reverse (1122314010031), we get a palindrome (14123355332141).

The spelling of 13001041322110 in words is "thirteen trillion, one billion, forty-one million, three hundred twenty-two thousand, one hundred ten".

Divisors: 1 2 5 10 1300104132211 2600208264422 6500520661055 13001041322110