13001100103 has 2 divisors, whose sum is σ = 13001100104. Its totient is φ = 13001100102.

The previous prime is 13001100067. The next prime is 13001100107. The reversal of 13001100103 is 30100110031.

13001100103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13001100103 is a prime.

It is a super-2 number, since 2×13001100103² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13001100103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13001100107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6500550051 + 6500550052.

It is an arithmetic number, because the mean of its divisors is an integer number (6500550052).

Almost surely, 2^13001100103 is an apocalyptic number.

13001100103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13001100103 is an equidigital number, since it uses as much as digits as its factorization.

13001100103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 13001100103 its reverse (30100110031), we get a palindrome (43101210134).

The spelling of 13001100103 in words is "thirteen billion, one million, one hundred thousand, one hundred three".