Search a number
-
+
13001111131 = 17764771243
BaseRepresentation
bin11000001101110110…
…10011011001011011
31020120001212212122111
430012323103121123
5203111241024011
65550030533151
7640115423041
oct140673233133
936501785574
1013001111131
115571874248
12262a0671b7
1312c26a0688
148b4978391
155115c1121
hex306ed365b

13001111131 has 4 divisors (see below), whose sum is σ = 13765882392. Its totient is φ = 12236339872.

The previous prime is 13001111129. The next prime is 13001111143. The reversal of 13001111131 is 13111110031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13001111131 - 21 = 13001111129 is a prime.

It is a super-2 number, since 2×130011111312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13001111161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 382385605 + ... + 382385638.

It is an arithmetic number, because the mean of its divisors is an integer number (3441470598).

Almost surely, 213001111131 is an apocalyptic number.

13001111131 is a deficient number, since it is larger than the sum of its proper divisors (764771261).

13001111131 is an equidigital number, since it uses as much as digits as its factorization.

13001111131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 764771260.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 13001111131 its reverse (13111110031), we get a palindrome (26112221162).

The spelling of 13001111131 in words is "thirteen billion, one million, one hundred eleven thousand, one hundred thirty-one".

Divisors: 1 17 764771243 13001111131