1300113030 has 64 divisors (see below), whose sum is σ = 3308064768. Its totient is φ = 326436480.

The previous prime is 1300112963. The next prime is 1300113043. The reversal of 1300113030 is 303110031.

It is a junction number, because it is equal to n+sod(n) for n = 1300112997 and 1300113015.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15519 + ... + 53301.

It is an arithmetic number, because the mean of its divisors is an integer number (51688512).

Almost surely, 2^1300113030 is an apocalyptic number.

1300113030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300113030, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1654032384).

1300113030 is an abundant number, since it is smaller than the sum of its proper divisors (2007951738).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300113030 is a wasteful number, since it uses less digits than its factorization.

1300113030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 37861.

The product of its (nonzero) digits is 27, while the sum is 12.

The square root of 1300113030 is about 36057.0801646500. The cubic root of 1300113030 is about 1091.4245129489.

Adding to 1300113030 its reverse (303110031), we get a palindrome (1603223061).

Subtracting from 1300113030 its reverse (303110031), we obtain a cube (997002999 = 999³).

The spelling of 1300113030 in words is "one billion, three hundred million, one hundred thirteen thousand, thirty".