130011439 has 2 divisors, whose sum is σ = 130011440. Its totient is φ = 130011438.

The previous prime is 130011419. The next prime is 130011443. The reversal of 130011439 is 934110031.

It is a strong prime.

It is an emirp because it is prime and its reverse (934110031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130011439 - 2⁵ = 130011407 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130011419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65005719 + 65005720.

It is an arithmetic number, because the mean of its divisors is an integer number (65005720).

Almost surely, 2^130011439 is an apocalyptic number.

130011439 is a deficient number, since it is larger than the sum of its proper divisors (1).

130011439 is an equidigital number, since it uses as much as digits as its factorization.

130011439 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 22.

The square root of 130011439 is about 11402.2558732910. The cubic root of 130011439 is about 506.5945598466.

The spelling of 130011439 in words is "one hundred thirty million, eleven thousand, four hundred thirty-nine".