Base | Representation |
---|---|
bin | 111100100010101010… |
… | …0011011101100100111 |
3 | 110102120202112001210111 |
4 | 1321011110123230213 |
5 | 4112231033044421 |
6 | 135420544233451 |
7 | 12251550535564 |
oct | 1710524335447 |
9 | 412522461714 |
10 | 130012003111 |
11 | 50157428261 |
12 | 2124490b887 |
13 | c34c518073 |
14 | 6414d1186b |
15 | 35ade34ee1 |
hex | 1e4551bb27 |
130012003111 has 2 divisors, whose sum is σ = 130012003112. Its totient is φ = 130012003110.
The previous prime is 130012003097. The next prime is 130012003127. The reversal of 130012003111 is 111300210031.
It is a weak prime.
It is an emirp because it is prime and its reverse (111300210031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 130012003111 - 29 = 130012002599 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130012003091 and 130012003100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130012003211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006001555 + 65006001556.
It is an arithmetic number, because the mean of its divisors is an integer number (65006001556).
Almost surely, 2130012003111 is an apocalyptic number.
130012003111 is a deficient number, since it is larger than the sum of its proper divisors (1).
130012003111 is an equidigital number, since it uses as much as digits as its factorization.
130012003111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 130012003111 its reverse (111300210031), we get a palindrome (241312213142).
The spelling of 130012003111 in words is "one hundred thirty billion, twelve million, three thousand, one hundred eleven".
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