130012012021110 has 32 divisors (see below), whose sum is σ = 312029203505760. Its totient is φ = 34669828243968.

The previous prime is 130012012021109. The next prime is 130012012021147. The reversal of 130012012021110 is 11120210210031.

It is a super-2 number, since 2×130012012021110² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 130012012021110.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29153884 + ... + 33316256.

It is an arithmetic number, because the mean of its divisors is an integer number (9750912609555).

Almost surely, 2^{130012012021110} is an apocalyptic number.

130012012021110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130012012021110 is an abundant number, since it is smaller than the sum of its proper divisors (182017191484650).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130012012021110 is a wasteful number, since it uses less digits than its factorization.

130012012021110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5203552.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 130012012021110 its reverse (11120210210031), we get a palindrome (141132222231141).

The spelling of 130012012021110 in words is "one hundred thirty trillion, twelve billion, twelve million, twenty-one thousand, one hundred ten".