Base | Representation |
---|---|
bin | 11101100011111011001001… |
… | …000010111100111001001011 |
3 | 122001100000210010022021000201 |
4 | 131203323021002330321023 |
5 | 114020104120424402133 |
6 | 1140302411535513031 |
7 | 36246026243662513 |
oct | 3543731102747113 |
9 | 561300703267021 |
10 | 130012033044043 |
11 | 38475880279327 |
12 | 126b9252988777 |
13 | 577110b5193a7 |
14 | 241688a33c843 |
15 | 1006da0b94d7d |
hex | 763ec90bce4b |
130012033044043 has 4 divisors (see below), whose sum is σ = 130013664657520. Its totient is φ = 130010401430568.
The previous prime is 130012033044037. The next prime is 130012033044083. The reversal of 130012033044043 is 340440330210031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130012033044043 - 25 = 130012033044011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130012033044083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 815687208 + ... + 815846581.
It is an arithmetic number, because the mean of its divisors is an integer number (32503416164380).
Almost surely, 2130012033044043 is an apocalyptic number.
130012033044043 is a deficient number, since it is larger than the sum of its proper divisors (1631613477).
130012033044043 is an equidigital number, since it uses as much as digits as its factorization.
130012033044043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1631613476.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 130012033044043 its reverse (340440330210031), we get a palindrome (470452363254074).
The spelling of 130012033044043 in words is "one hundred thirty trillion, twelve billion, thirty-three million, forty-four thousand, forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.089 sec. • engine limits •