Base | Representation |
---|---|
bin | 111100100010101011… |
… | …0000111001110101001 |
3 | 110102120210100102222110 |
4 | 1321011112013032221 |
5 | 4112231141143221 |
6 | 135421001512533 |
7 | 12251554351650 |
oct | 1710526071651 |
9 | 412523312873 |
10 | 130012443561 |
11 | 501576a9170 |
12 | 21244aa2749 |
13 | c34c6406a0 |
14 | 6414dc8197 |
15 | 35adec0776 |
hex | 1e455873a9 |
130012443561 has 128 divisors (see below), whose sum is σ = 241184563200. Its totient is φ = 60091637760.
The previous prime is 130012443559. The next prime is 130012443563. The reversal of 130012443561 is 165344210031.
It is an interprime number because it is at equal distance from previous prime (130012443559) and next prime (130012443563).
It is not a de Polignac number, because 130012443561 - 21 = 130012443559 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130012443563) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 80903020 + ... + 80904626.
It is an arithmetic number, because the mean of its divisors is an integer number (1884254400).
Almost surely, 2130012443561 is an apocalyptic number.
130012443561 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
130012443561 is a deficient number, since it is larger than the sum of its proper divisors (111172119639).
130012443561 is a wasteful number, since it uses less digits than its factorization.
130012443561 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2599.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 130012443561 its reverse (165344210031), we get a palindrome (295356653592).
The spelling of 130012443561 in words is "one hundred thirty billion, twelve million, four hundred forty-three thousand, five hundred sixty-one".
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