Base | Representation |
---|---|
bin | 111100100010101100… |
… | …0001111000111001111 |
3 | 110102120211101201110121 |
4 | 1321011120033013033 |
5 | 4112231312001033 |
6 | 135421021445411 |
7 | 12251562160435 |
oct | 1710530170717 |
9 | 412524351417 |
10 | 130013000143 |
11 | 50157a49354 |
12 | 21245110867 |
13 | c34c7a6b20 |
14 | 64150d0d55 |
15 | 35ae08062d |
hex | 1e4560f1cf |
130013000143 has 4 divisors (see below), whose sum is σ = 140014000168. Its totient is φ = 120012000120.
The previous prime is 130013000123. The next prime is 130013000167. The reversal of 130013000143 is 341000310031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130013000143 - 217 = 130012869071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130013000123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000499993 + ... + 5000500018.
It is an arithmetic number, because the mean of its divisors is an integer number (35003500042).
Almost surely, 2130013000143 is an apocalyptic number.
130013000143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
130013000143 is a deficient number, since it is larger than the sum of its proper divisors (10001000025).
130013000143 is a wasteful number, since it uses less digits than its factorization.
130013000143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10001000024.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 130013000143 its reverse (341000310031), we get a palindrome (471013310174).
The spelling of 130013000143 in words is "one hundred thirty billion, thirteen million, one hundred forty-three", and thus it is an aban number.
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