Base | Representation |
---|---|
bin | 10010111010110101110… |
… | …011001101000010010111 |
3 | 11121021212022101102112202 |
4 | 102322311303031002113 |
5 | 132300131314102411 |
6 | 2433134354435115 |
7 | 162634303356131 |
oct | 22726563150227 |
9 | 4537768342482 |
10 | 1300130222231 |
11 | 461422686075 |
12 | 18bb82b92a9b |
13 | 957a9090109 |
14 | 46cd89a6051 |
15 | 23c4559983b |
hex | 12eb5ccd097 |
1300130222231 has 2 divisors, whose sum is σ = 1300130222232. Its totient is φ = 1300130222230.
The previous prime is 1300130222219. The next prime is 1300130222233. The reversal of 1300130222231 is 1322220310031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1300130222231 - 226 = 1300063113367 is a prime.
It is a super-2 number, since 2×13001302222312 (a number of 25 digits) contains 22 as substring.
Together with 1300130222233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300130222233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650065111115 + 650065111116.
It is an arithmetic number, because the mean of its divisors is an integer number (650065111116).
Almost surely, 21300130222231 is an apocalyptic number.
1300130222231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300130222231 is an equidigital number, since it uses as much as digits as its factorization.
1300130222231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1300130222231 its reverse (1322220310031), we get a palindrome (2622350532262).
The spelling of 1300130222231 in words is "one trillion, three hundred billion, one hundred thirty million, two hundred twenty-two thousand, two hundred thirty-one".
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