Base | Representation |
---|---|
bin | 11101100011111100001010… |
… | …011011100010111010111111 |
3 | 122001100010121120102220211201 |
4 | 131203330022123202322333 |
5 | 114020113342240312203 |
6 | 1140303112443400331 |
7 | 36246065364022051 |
oct | 3543741233427277 |
9 | 561303546386751 |
10 | 130013130010303 |
11 | 38476293501311 |
12 | 126b94ba2230a7 |
13 | 5771254877257 |
14 | 2416951ccb8d1 |
15 | 1006e1712be1d |
hex | 763f0a6e2ebf |
130013130010303 has 2 divisors, whose sum is σ = 130013130010304. Its totient is φ = 130013130010302.
The previous prime is 130013130010277. The next prime is 130013130010367. The reversal of 130013130010303 is 303010031310031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130013130010303 - 25 = 130013130010271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130013130010373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006565005151 + 65006565005152.
It is an arithmetic number, because the mean of its divisors is an integer number (65006565005152).
Almost surely, 2130013130010303 is an apocalyptic number.
130013130010303 is a deficient number, since it is larger than the sum of its proper divisors (1).
130013130010303 is an equidigital number, since it uses as much as digits as its factorization.
130013130010303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 243, while the sum is 19.
Adding to 130013130010303 its reverse (303010031310031), we get a palindrome (433023161320334).
The spelling of 130013130010303 in words is "one hundred thirty trillion, thirteen billion, one hundred thirty million, ten thousand, three hundred three".
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