Base | Representation |
---|---|
bin | 11101100011111100010101… |
… | …010010100010111010000001 |
3 | 122001100011002021021010120011 |
4 | 131203330111102202322001 |
5 | 114020114230410402241 |
6 | 1140303142512344521 |
7 | 36246103035431224 |
oct | 3543742522427201 |
9 | 561304067233504 |
10 | 130013312200321 |
11 | 3847637732a380 |
12 | 126b954b245141 |
13 | 5771283536bb4 |
14 | 241696c1955bb |
15 | 1006e28119281 |
hex | 763f154a2e81 |
130013312200321 has 8 divisors (see below), whose sum is σ = 141833330200800. Its totient is φ = 118193398530240.
The previous prime is 130013312200297. The next prime is 130013312200337. The reversal of 130013312200321 is 123002213310031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 130013312200321 - 221 = 130013310103169 is a prime.
It is a super-2 number, since 2×1300133122003212 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130013312200292 and 130013312200301.
It is not an unprimeable number, because it can be changed into a prime (130013312200361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23465551 + ... + 28472068.
It is an arithmetic number, because the mean of its divisors is an integer number (17729166275100).
Almost surely, 2130013312200321 is an apocalyptic number.
130013312200321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
130013312200321 is a deficient number, since it is larger than the sum of its proper divisors (11820018000479).
130013312200321 is a wasteful number, since it uses less digits than its factorization.
130013312200321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52165199.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 130013312200321 its reverse (123002213310031), we get a palindrome (253015525510352).
The spelling of 130013312200321 in words is "one hundred thirty trillion, thirteen billion, three hundred twelve million, two hundred thousand, three hundred twenty-one".
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