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130015054533500 = 2253260030109067
BaseRepresentation
bin11101100011111101111101…
…001001000001001101111100
3122001100022120200202211100122
4131203331331021001031330
5114020131312430033000
61140304031432514112
736246164153136623
oct3543757511011574
9561308520684318
10130015054533500
1138477090887054
12126b995684b938
1357714a04b5c86
142416a9573a6ba
151006ecb081085
hex763f7d24137c

130015054533500 has 24 divisors (see below), whose sum is σ = 283952879102256. Its totient is φ = 52006021813200.

The previous prime is 130015054533449. The next prime is 130015054533523. The reversal of 130015054533500 is 5335450510031.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 130015054034 + ... + 130015055033.

It is an arithmetic number, because the mean of its divisors is an integer number (11831369962594).

Almost surely, 2130015054533500 is an apocalyptic number.

130015054533500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130015054533500 is an abundant number, since it is smaller than the sum of its proper divisors (153937824568756).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130015054533500 is a wasteful number, since it uses less digits than its factorization.

130015054533500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 260030109086 (or 260030109074 counting only the distinct ones).

The product of its (nonzero) digits is 67500, while the sum is 35.

The spelling of 130015054533500 in words is "one hundred thirty trillion, fifteen billion, fifty-four million, five hundred thirty-three thousand, five hundred".

Divisors: 1 2 4 5 10 20 25 50 100 125 250 500 260030109067 520060218134 1040120436268 1300150545335 2600301090670 5200602181340 6500752726675 13001505453350 26003010906700 32503763633375 65007527266750 130015054533500