Base | Representation |
---|---|
bin | 11000001101111001… |
… | …11100110101111011 |
3 | 1020120002200211002221 |
4 | 30012330330311323 |
5 | 203111343334120 |
6 | 5550044104511 |
7 | 640122202165 |
oct | 140674746573 |
9 | 36502624087 |
10 | 13001543035 |
11 | 5572039798 |
12 | 262a235137 |
13 | 12c27c2140 |
14 | 8b4a4b935 |
15 | 5116590aa |
hex | 306f3cd7b |
13001543035 has 32 divisors (see below), whose sum is σ = 17286212160. Its totient is φ = 9325352448.
The previous prime is 13001543029. The next prime is 13001543053. The reversal of 13001543035 is 53034510031.
It is a cyclic number.
It is not a de Polignac number, because 13001543035 - 27 = 13001542907 is a prime.
It is a super-3 number, since 3×130015430353 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1469856 + ... + 1478674.
It is an arithmetic number, because the mean of its divisors is an integer number (540194130).
Almost surely, 213001543035 is an apocalyptic number.
13001543035 is a deficient number, since it is larger than the sum of its proper divisors (4284669125).
13001543035 is a wasteful number, since it uses less digits than its factorization.
13001543035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9487.
The product of its (nonzero) digits is 2700, while the sum is 25.
The spelling of 13001543035 in words is "thirteen billion, one million, five hundred forty-three thousand, thirty-five".
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