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13002003141 = 34334001047
BaseRepresentation
bin11000001101111101…
…01101001011000101
31020120010120012020220
430012332231023011
5203112003100031
65550102014553
7640126126461
oct140676551305
936503505226
1013002003141
115572323446
12262a417459
1312c29236aa
148b4b2b4a1
155116ea596
hex306fad2c5

13002003141 has 4 divisors (see below), whose sum is σ = 17336004192. Its totient is φ = 8668002092.

The previous prime is 13002003103. The next prime is 13002003143. The reversal of 13002003141 is 14130020031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13002003141 - 214 = 13001986757 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13002003141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13002003143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167000521 + ... + 2167000526.

It is an arithmetic number, because the mean of its divisors is an integer number (4334001048).

Almost surely, 213002003141 is an apocalyptic number.

It is an amenable number.

13002003141 is a deficient number, since it is larger than the sum of its proper divisors (4334001051).

13002003141 is an equidigital number, since it uses as much as digits as its factorization.

13002003141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4334001050.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 13002003141 its reverse (14130020031), we get a palindrome (27132023172).

The spelling of 13002003141 in words is "thirteen billion, two million, three thousand, one hundred forty-one".

Divisors: 1 3 4334001047 13002003141