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1300202121103 = 3806573415679
BaseRepresentation
bin10010111010111010000…
…101011110011110001111
311121022001022200021020221
4102322322011132132033
5132300303220333403
62433145443452211
7162636135451624
oct22727205363617
94538038607227
101300202121103
1146145a223826
1218bba3087067
13957bac45022
1446d0436034b
1523c4ba4cdbd
hex12eba15e78f

1300202121103 has 4 divisors (see below), whose sum is σ = 1300205917440. Its totient is φ = 1300198324768.

The previous prime is 1300202121067. The next prime is 1300202121139. The reversal of 1300202121103 is 3011212020031.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1300202121067) and next prime (1300202121139).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1300202121103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300202121403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1327183 + ... + 2088496.

It is an arithmetic number, because the mean of its divisors is an integer number (325051479360).

Almost surely, 21300202121103 is an apocalyptic number.

1300202121103 is a deficient number, since it is larger than the sum of its proper divisors (3796337).

1300202121103 is an equidigital number, since it uses as much as digits as its factorization.

1300202121103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3796336.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1300202121103 its reverse (3011212020031), we get a palindrome (4311414141134).

The spelling of 1300202121103 in words is "one trillion, three hundred billion, two hundred two million, one hundred twenty-one thousand, one hundred three".

Divisors: 1 380657 3415679 1300202121103