Base | Representation |
---|---|
bin | 111100100010111001… |
… | …1110010000100011101 |
3 | 110102121022222120220122 |
4 | 1321011303302010131 |
5 | 4112240134034323 |
6 | 135421440324325 |
7 | 12252010434221 |
oct | 1710563620435 |
9 | 412538876818 |
10 | 130020221213 |
11 | 50161030683 |
12 | 212476136a5 |
13 | c35113484c |
14 | 6416050781 |
15 | 35aea09ec8 |
hex | 1e45cf211d |
130020221213 has 4 divisors (see below), whose sum is σ = 132473432988. Its totient is φ = 127567009440.
The previous prime is 130020221189. The next prime is 130020221237. The reversal of 130020221213 is 312122020031.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (130020221189) and next prime (130020221237).
It can be written as a sum of positive squares in 2 ways, for example, as 60261903289 + 69758317924 = 245483^2 + 264118^2 .
It is a cyclic number.
It is not a de Polignac number, because 130020221213 - 222 = 130016026909 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 130020221191 and 130020221200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130020221273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1226605808 + ... + 1226605913.
It is an arithmetic number, because the mean of its divisors is an integer number (33118358247).
Almost surely, 2130020221213 is an apocalyptic number.
It is an amenable number.
130020221213 is a deficient number, since it is larger than the sum of its proper divisors (2453211775).
130020221213 is an equidigital number, since it uses as much as digits as its factorization.
130020221213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2453211774.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 130020221213 its reverse (312122020031), we get a palindrome (442142241244).
The spelling of 130020221213 in words is "one hundred thirty billion, twenty million, two hundred twenty-one thousand, two hundred thirteen".
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