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13002100000000 = 2858130021
BaseRepresentation
bin1011110100110100100110…
…0011010100010100000000
31201000222200201000120201021
42331031021203110110000
53201011300100000000
643353025434515224
72511241105325356
oct275151143242400
951028621016637
1013002100000000
114163183538891
12155ba88b95b14
13734128a76277
1432d43acb17d6
15178333bee11a
hexbd3498d4500

13002100000000 has 162 divisors, whose sum is σ = 32441996085002. Its totient is φ = 5200800000000.

The previous prime is 13002099999991. The next prime is 13002100000031. The reversal of 13002100000000 is 120031.

It can be written as a sum of positive squares in 9 ways, for example, as 983619634176 + 12018480365824 = 991776^2 + 3466768^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 99934990 + ... + 100065010.

Almost surely, 213002100000000 is an apocalyptic number.

13002100000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13002100000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16220998042501).

13002100000000 is an abundant number, since it is smaller than the sum of its proper divisors (19439896085002).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13002100000000 is an frugal number, since it uses more digits than its factorization.

13002100000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130077 (or 130028 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 7.

Adding to 13002100000000 its reverse (120031), we get a palindrome (13002100120031).

The spelling of 13002100000000 in words is "thirteen trillion, two billion, one hundred million", and thus it is an aban number.