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13002101134144 = 261078918830089
BaseRepresentation
bin1011110100110100100110…
…0111101001001101000000
31201000222200210011012110121
42331031021213221031000
53201011300342243034
643353025515110024
72511241121061043
oct275151147511500
951028623135417
1013002101134144
1141631841429a1
12155ba89442314
13734129082565
1432d43b0c8c5a
15178333d751b4
hexbd3499e9340

13002101134144 has 28 divisors (see below), whose sum is σ = 25803437229700. Its totient is φ = 6500447659008.

The previous prime is 13002101134133. The next prime is 13002101134201. The reversal of 13002101134144 is 44143110120031.

It can be written as a sum of positive squares in 2 ways, for example, as 9816190286400 + 3185910847744 = 3133080^2 + 1784912^2 .

It is a super-2 number, since 2×130021011341442 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8724549 + ... + 10105540.

Almost surely, 213002101134144 is an apocalyptic number.

It is an amenable number.

13002101134144 is a deficient number, since it is larger than the sum of its proper divisors (12801336095556).

13002101134144 is a wasteful number, since it uses less digits than its factorization.

13002101134144 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18840890 (or 18840880 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13002101134144 its reverse (44143110120031), we get a palindrome (57145211254175).

The spelling of 13002101134144 in words is "thirteen trillion, two billion, one hundred one million, one hundred thirty-four thousand, one hundred forty-four".

Divisors: 1 2 4 8 16 32 64 10789 21578 43156 86312 172624 345248 690496 18830089 37660178 75320356 150640712 301281424 602562848 1205125696 203157830221 406315660442 812631320884 1625262641768 3250525283536 6501050567072 13002101134144