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1300212535421 is a prime number
BaseRepresentation
bin10010111010111010101…
…101001101000001111101
311121022002001021101000102
4102322322231031001331
5132300313402113141
62433150455010445
7162636323125232
oct22727255150175
94538061241012
101300212535421
114614650971a8
1218bba6669a25
13957c0150347
1446d058b1789
1523c4c90899b
hex12ebab4d07d

1300212535421 has 2 divisors, whose sum is σ = 1300212535422. Its totient is φ = 1300212535420.

The previous prime is 1300212535387. The next prime is 1300212535429. The reversal of 1300212535421 is 1245352120031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1254711379321 + 45501156100 = 1120139^2 + 213310^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300212535421 - 214 = 1300212519037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300212535429) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650106267710 + 650106267711.

It is an arithmetic number, because the mean of its divisors is an integer number (650106267711).

Almost surely, 21300212535421 is an apocalyptic number.

It is an amenable number.

1300212535421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300212535421 is an equidigital number, since it uses as much as digits as its factorization.

1300212535421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 1300212535421 its reverse (1245352120031), we get a palindrome (2545564655452).

The spelling of 1300212535421 in words is "one trillion, three hundred billion, two hundred twelve million, five hundred thirty-five thousand, four hundred twenty-one".