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130021312117 is a prime number
BaseRepresentation
bin111100100010111011…
…1111100011001110101
3110102121102001000100111
41321011313330121311
54112240423441432
6135421515543021
712252022626544
oct1710567743165
9412542030314
10130021312117
1150161706254
1221247a5aa71
13c351427258
14641625615b
1535aeb73347
hex1e45dfc675

130021312117 has 2 divisors, whose sum is σ = 130021312118. Its totient is φ = 130021312116.

The previous prime is 130021312103. The next prime is 130021312123. The reversal of 130021312117 is 711213120031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100184277361 + 29837034756 = 316519^2 + 172734^2 .

It is an emirp because it is prime and its reverse (711213120031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130021312117 - 27 = 130021311989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130021319117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65010656058 + 65010656059.

It is an arithmetic number, because the mean of its divisors is an integer number (65010656059).

Almost surely, 2130021312117 is an apocalyptic number.

It is an amenable number.

130021312117 is a deficient number, since it is larger than the sum of its proper divisors (1).

130021312117 is an equidigital number, since it uses as much as digits as its factorization.

130021312117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 130021312117 its reverse (711213120031), we get a palindrome (841234432148).

The spelling of 130021312117 in words is "one hundred thirty billion, twenty-one million, three hundred twelve thousand, one hundred seventeen".