Base | Representation |
---|---|
bin | 11101100100000011110010… |
… | …101101111011111111101000 |
3 | 122001100220202111022212002201 |
4 | 131210003302231323333220 |
5 | 114020232131430104000 |
6 | 1140310545404505544 |
7 | 36246505366525303 |
oct | 3544036255737750 |
9 | 561326674285081 |
10 | 130021322113000 |
11 | 3847980775831a |
12 | 126bb00584b2b4 |
13 | 5771c5bb3abb6 |
14 | 24170cbcbdb3a |
15 | 100724642196a |
hex | 7640f2b7bfe8 |
130021322113000 has 64 divisors (see below), whose sum is σ = 304251620587200. Its totient is φ = 52008233659200.
The previous prime is 130021322112961. The next prime is 130021322113037. The reversal of 130021322113000 is 311223120031.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 290483371 + ... + 290930629.
It is an arithmetic number, because the mean of its divisors is an integer number (4753931571675).
Almost surely, 2130021322113000 is an apocalyptic number.
130021322113000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130021322113000 is an abundant number, since it is smaller than the sum of its proper divisors (174230298474200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130021322113000 is a wasteful number, since it uses less digits than its factorization.
130021322113000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 737987 (or 737973 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 130021322113000 its reverse (311223120031), we get a palindrome (130332545233031).
The spelling of 130021322113000 in words is "one hundred thirty trillion, twenty-one billion, three hundred twenty-two million, one hundred thirteen thousand".
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