Base | Representation |
---|---|
bin | 1011110100110101000000… |
… | …1011100101101000111111 |
3 | 1201000222222110022010220200 |
4 | 2331031100023211220333 |
5 | 3201012012033020111 |
6 | 43353044450414543 |
7 | 2511243625561125 |
oct | 275152013455077 |
9 | 51028873263820 |
10 | 13002211220031 |
11 | 41632302a3070 |
12 | 155baba291453 |
13 | 734145b17a37 |
14 | 32d44b983915 |
15 | 17833d86d256 |
hex | bd3502e5a3f |
13002211220031 has 48 divisors (see below), whose sum is σ = 20967683193600. Its totient is φ = 7695812799360.
The previous prime is 13002211220029. The next prime is 13002211220069.
13002211220031 is a `hidden beast` number, since 1 + 300 + 22 + 112 + 200 + 31 = 666.
13002211220031 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 13002211220031 - 21 = 13002211220029 is a prime.
It is a super-2 number, since 2×130022112200312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13002211219986 and 13002211220013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13002211220081) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 31368270 + ... + 31780068.
It is an arithmetic number, because the mean of its divisors is an integer number (436826733200).
Almost surely, 213002211220031 is an apocalyptic number.
13002211220031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13002211220031 is a deficient number, since it is larger than the sum of its proper divisors (7965471973569).
13002211220031 is a wasteful number, since it uses less digits than its factorization.
13002211220031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 419276 (or 419273 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
It can be divided in two parts, 1300221 and 1220031, that added together give a palindrome (2520252).
The spelling of 13002211220031 in words is "thirteen trillion, two billion, two hundred eleven million, two hundred twenty thousand, thirty-one".
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