Base | Representation |
---|---|
bin | 11101100100000100100010… |
… | …010101100010011000101101 |
3 | 122001100222211011121200121202 |
4 | 131210010202111202120231 |
5 | 114020240300440214041 |
6 | 1140311200544135245 |
7 | 36246534240252113 |
oct | 3544044225423055 |
9 | 561328734550552 |
10 | 130022121023021 |
11 | 3847a087714237 |
12 | 126bb1a9307525 |
13 | 57720584cb916 |
14 | 2417166043ab3 |
15 | 1007291630a9b |
hex | 76412256262d |
130022121023021 has 8 divisors (see below), whose sum is σ = 130036990758840. Its totient is φ = 130007251846912.
The previous prime is 130022121023017. The next prime is 130022121023083. The reversal of 130022121023021 is 120320121220031.
It can be written as a sum of positive squares in 4 ways, for example, as 4544647396 + 130017576375625 = 67414^2 + 11402525^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130022121023021 - 22 = 130022121023017 is a prime.
It is a super-2 number, since 2×1300221210230212 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130022121022984 and 130022121023002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130022121022021) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 610690241 + ... + 610903113.
It is an arithmetic number, because the mean of its divisors is an integer number (16254623844855).
Almost surely, 2130022121023021 is an apocalyptic number.
It is an amenable number.
130022121023021 is a deficient number, since it is larger than the sum of its proper divisors (14869735819).
130022121023021 is a wasteful number, since it uses less digits than its factorization.
130022121023021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 279855.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 130022121023021 its reverse (120320121220031), we get a palindrome (250342242243052).
The spelling of 130022121023021 in words is "one hundred thirty trillion, twenty-two billion, one hundred twenty-one million, twenty-three thousand, twenty-one".
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