Base | Representation |
---|---|
bin | 1011110100110101000101… |
… | …0011001110101000001111 |
3 | 1201001000000202122021101101 |
4 | 2331031101103032220033 |
5 | 3201012031340001033 |
6 | 43353050401123531 |
7 | 2511244244316466 |
oct | 275152123165017 |
9 | 51030022567341 |
10 | 13002230000143 |
11 | 416323a95a91a |
12 | 155bb046295a7 |
13 | 734149991b27 |
14 | 32d4502719dd |
15 | 17834032c97d |
hex | bd3514cea0f |
13002230000143 has 2 divisors, whose sum is σ = 13002230000144. Its totient is φ = 13002230000142.
The previous prime is 13002230000099. The next prime is 13002230000317. The reversal of 13002230000143 is 34100003220031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13002230000143 - 229 = 13001693129231 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13002230000143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13002230000843) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501115000071 + 6501115000072.
It is an arithmetic number, because the mean of its divisors is an integer number (6501115000072).
Almost surely, 213002230000143 is an apocalyptic number.
13002230000143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002230000143 is an equidigital number, since it uses as much as digits as its factorization.
13002230000143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13002230000143 its reverse (34100003220031), we get a palindrome (47102233220174).
The spelling of 13002230000143 in words is "thirteen trillion, two billion, two hundred thirty million, one hundred forty-three", and thus it is an aban number.
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