1300223190941 has 2 divisors, whose sum is σ = 1300223190942. Its totient is φ = 1300223190940.

The previous prime is 1300223190913. The next prime is 1300223190943. The reversal of 1300223190941 is 1490913220031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1196954154916 + 103269036025 = 1094054^2 + 321355^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300223190941 - 2¹⁴ = 1300223174557 is a prime.

It is a super-2 number, since 2×1300223190941² (a number of 25 digits) contains 22 as substring.

Together with 1300223190943, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300223190943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650111595470 + 650111595471.

It is an arithmetic number, because the mean of its divisors is an integer number (650111595471).

Almost surely, 2^{1300223190941} is an apocalyptic number.

It is an amenable number.

1300223190941 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300223190941 is an equidigital number, since it uses as much as digits as its factorization.

1300223190941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11664, while the sum is 35.

The spelling of 1300223190941 in words is "one trillion, three hundred billion, two hundred twenty-three million, one hundred ninety thousand, nine hundred forty-one".