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130022322002141 is a prime number
BaseRepresentation
bin11101100100000100101110…
…010100001101100011011101
3122001101000100011210111010212
4131210010232110031203131
5114020241203413032031
61140311232523542205
736246542230455062
oct3544045624154335
9561330304714125
10130022322002141
113847a180105888
12126bb24468a965
13577208b03978a
1424171849dcc69
1510072a40d012b
hex76412e50d8dd

130022322002141 has 2 divisors, whose sum is σ = 130022322002142. Its totient is φ = 130022322002140.

The previous prime is 130022322002099. The next prime is 130022322002147. The reversal of 130022322002141 is 141200223220031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86407788945241 + 43614533056900 = 9295579^2 + 6604130^2 .

It is a cyclic number.

It is not a de Polignac number, because 130022322002141 - 214 = 130022321985757 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130022322002147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011161001070 + 65011161001071.

It is an arithmetic number, because the mean of its divisors is an integer number (65011161001071).

Almost surely, 2130022322002141 is an apocalyptic number.

It is an amenable number.

130022322002141 is a deficient number, since it is larger than the sum of its proper divisors (1).

130022322002141 is an equidigital number, since it uses as much as digits as its factorization.

130022322002141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 130022322002141 its reverse (141200223220031), we get a palindrome (271222545222172).

The spelling of 130022322002141 in words is "one hundred thirty trillion, twenty-two billion, three hundred twenty-two million, two thousand, one hundred forty-one".