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13002312111 = 34334104037
BaseRepresentation
bin11000001101111111…
…11000100110101111
31020120011010220002020
430012333320212233
5203112042441421
65550112401223
7640131554325
oct140677704657
936504126066
1013002312111
115572514598
12262a546213
1312c2a01209
148b4babd15
1551175bdc6
hex306ff89af

13002312111 has 4 divisors (see below), whose sum is σ = 17336416152. Its totient is φ = 8668208072.

The previous prime is 13002312107. The next prime is 13002312131. The reversal of 13002312111 is 11121320031.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13002312111 - 22 = 13002312107 is a prime.

It is a super-3 number, since 3×130023121113 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13002312101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167052016 + ... + 2167052021.

It is an arithmetic number, because the mean of its divisors is an integer number (4334104038).

Almost surely, 213002312111 is an apocalyptic number.

13002312111 is a deficient number, since it is larger than the sum of its proper divisors (4334104041).

13002312111 is an equidigital number, since it uses as much as digits as its factorization.

13002312111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4334104040.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 13002312111 its reverse (11121320031), we get a palindrome (24123632142).

The spelling of 13002312111 in words is "thirteen billion, two million, three hundred twelve thousand, one hundred eleven".

Divisors: 1 3 4334104037 13002312111