Base | Representation |
---|---|
bin | 11101100100000101100010… |
… | …110101110010101011111101 |
3 | 122001101002121120222000002112 |
4 | 131210011202311302223331 |
5 | 114020300010011021341 |
6 | 1140311500203303405 |
7 | 36246603120630023 |
oct | 3544054265625375 |
9 | 561332546860075 |
10 | 130023203220221 |
11 | 3847a592579a93 |
12 | 126bb44b81ab65 |
13 | 577219b7882ac |
14 | 2417229a6a713 |
15 | 100730664baeb |
hex | 764162d72afd |
130023203220221 has 2 divisors, whose sum is σ = 130023203220222. Its totient is φ = 130023203220220.
The previous prime is 130023203220109. The next prime is 130023203220247. The reversal of 130023203220221 is 122022302320031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 85898882467225 + 44124320752996 = 9268165^2 + 6642614^2 .
It is a cyclic number.
It is not a de Polignac number, because 130023203220221 - 210 = 130023203219197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130023203210221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011601610110 + 65011601610111.
It is an arithmetic number, because the mean of its divisors is an integer number (65011601610111).
Almost surely, 2130023203220221 is an apocalyptic number.
It is an amenable number.
130023203220221 is a deficient number, since it is larger than the sum of its proper divisors (1).
130023203220221 is an equidigital number, since it uses as much as digits as its factorization.
130023203220221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 130023203220221 its reverse (122022302320031), we get a palindrome (252045505540252).
The spelling of 130023203220221 in words is "one hundred thirty trillion, twenty-three billion, two hundred three million, two hundred twenty thousand, two hundred twenty-one".
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