130023212033113 has 4 divisors (see below), whose sum is σ = 148597956609280. Its totient is φ = 111448467456948.

The previous prime is 130023212033093. The next prime is 130023212033123. The reversal of 130023212033113 is 311330212320031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130023212033113 is a prime.

It is a super-2 number, since 2×130023212033113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130023212033123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9287372288073 + ... + 9287372288086.

It is an arithmetic number, because the mean of its divisors is an integer number (37149489152320).

Almost surely, 2^{130023212033113} is an apocalyptic number.

It is an amenable number.

130023212033113 is a deficient number, since it is larger than the sum of its proper divisors (18574744576167).

130023212033113 is an equidigital number, since it uses as much as digits as its factorization.

130023212033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18574744576166.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 130023212033113 its reverse (311330212320031), we get a palindrome (441353424353144).

The spelling of 130023212033113 in words is "one hundred thirty trillion, twenty-three billion, two hundred twelve million, thirty-three thousand, one hundred thirteen".