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130024141111343 is a prime number
BaseRepresentation
bin11101100100000110011010…
…101111100100000000101111
3122001101012000221202210211202
4131210012122233210000233
5114020303420111030333
61140312133225440115
736246635266601333
oct3544063257440057
9561335027683752
10130024141111343
113847aa23a31516
12126bb67194003b
1357722bab8a65b
1424172b844b7c3
15100735db605e8
hex76419abe402f

130024141111343 has 2 divisors, whose sum is σ = 130024141111344. Its totient is φ = 130024141111342.

The previous prime is 130024141111303. The next prime is 130024141111357. The reversal of 130024141111343 is 343111141420031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130024141111343 - 218 = 130024140849199 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130024141111303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012070555671 + 65012070555672.

It is an arithmetic number, because the mean of its divisors is an integer number (65012070555672).

Almost surely, 2130024141111343 is an apocalyptic number.

130024141111343 is a deficient number, since it is larger than the sum of its proper divisors (1).

130024141111343 is an equidigital number, since it uses as much as digits as its factorization.

130024141111343 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 130024141111343 its reverse (343111141420031), we get a palindrome (473135282531374).

The spelling of 130024141111343 in words is "one hundred thirty trillion, twenty-four billion, one hundred forty-one million, one hundred eleven thousand, three hundred forty-three".