Base | Representation |
---|---|
bin | 11101100100000110011010… |
… | …101111100100000000101111 |
3 | 122001101012000221202210211202 |
4 | 131210012122233210000233 |
5 | 114020303420111030333 |
6 | 1140312133225440115 |
7 | 36246635266601333 |
oct | 3544063257440057 |
9 | 561335027683752 |
10 | 130024141111343 |
11 | 3847aa23a31516 |
12 | 126bb67194003b |
13 | 57722bab8a65b |
14 | 24172b844b7c3 |
15 | 100735db605e8 |
hex | 76419abe402f |
130024141111343 has 2 divisors, whose sum is σ = 130024141111344. Its totient is φ = 130024141111342.
The previous prime is 130024141111303. The next prime is 130024141111357. The reversal of 130024141111343 is 343111141420031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130024141111343 - 218 = 130024140849199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130024141111303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012070555671 + 65012070555672.
It is an arithmetic number, because the mean of its divisors is an integer number (65012070555672).
Almost surely, 2130024141111343 is an apocalyptic number.
130024141111343 is a deficient number, since it is larger than the sum of its proper divisors (1).
130024141111343 is an equidigital number, since it uses as much as digits as its factorization.
130024141111343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 29.
Adding to 130024141111343 its reverse (343111141420031), we get a palindrome (473135282531374).
The spelling of 130024141111343 in words is "one hundred thirty trillion, twenty-four billion, one hundred forty-one million, one hundred eleven thousand, three hundred forty-three".
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