Base | Representation |
---|---|
bin | 11000001110000000… |
… | …10110001101110111 |
3 | 1020120011101001110101 |
4 | 30013000112031313 |
5 | 203112110332044 |
6 | 5550115134531 |
7 | 640132601044 |
oct | 140700261567 |
9 | 36504331411 |
10 | 13002433399 |
11 | 557259772a |
12 | 262a5a4447 |
13 | 12c2a44497 |
14 | 8b4c001cb |
15 | 511782cd4 |
hex | 307016377 |
13002433399 has 2 divisors, whose sum is σ = 13002433400. Its totient is φ = 13002433398.
The previous prime is 13002433387. The next prime is 13002433441. The reversal of 13002433399 is 99333420031.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (99333420031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13002433399 - 221 = 13000336247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13002433319) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501216699 + 6501216700.
It is an arithmetic number, because the mean of its divisors is an integer number (6501216700).
Almost surely, 213002433399 is an apocalyptic number.
13002433399 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002433399 is an equidigital number, since it uses as much as digits as its factorization.
13002433399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 37.
The spelling of 13002433399 in words is "thirteen billion, two million, four hundred thirty-three thousand, three hundred ninety-nine".
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