Base | Representation |
---|---|
bin | 11000001110000000… |
… | …10110011001011101 |
3 | 1020120011101002110212 |
4 | 30013000112121131 |
5 | 203112110343031 |
6 | 5550115142205 |
7 | 640132603154 |
oct | 140700263135 |
9 | 36504332425 |
10 | 13002434141 |
11 | 5572598244 |
12 | 262a5a4965 |
13 | 12c2a44918 |
14 | 8b4c0059b |
15 | 51178312b |
hex | 30701665d |
13002434141 has 4 divisors (see below), whose sum is σ = 13686772800. Its totient is φ = 12318095484.
The previous prime is 13002434131. The next prime is 13002434147. The reversal of 13002434141 is 14143420031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13002434141 - 230 = 11928692317 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13002434147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342169301 + ... + 342169338.
It is an arithmetic number, because the mean of its divisors is an integer number (3421693200).
Almost surely, 213002434141 is an apocalyptic number.
It is an amenable number.
13002434141 is a deficient number, since it is larger than the sum of its proper divisors (684338659).
13002434141 is an equidigital number, since it uses as much as digits as its factorization.
13002434141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 684338658.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13002434141 its reverse (14143420031), we get a palindrome (27145854172).
The spelling of 13002434141 in words is "thirteen billion, two million, four hundred thirty-four thousand, one hundred forty-one".
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