130025425311053 has 2 divisors, whose sum is σ = 130025425311054. Its totient is φ = 130025425311052.

The previous prime is 130025425311029. The next prime is 130025425311107. The reversal of 130025425311053 is 350113524520031.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79048067246404 + 50977358064649 = 8890898^2 + 7139843^2 .

It is a cyclic number.

It is not a de Polignac number, because 130025425311053 - 2¹⁰ = 130025425310029 is a prime.

It is a super-2 number, since 2×130025425311053² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130025425311013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012712655526 + 65012712655527.

It is an arithmetic number, because the mean of its divisors is an integer number (65012712655527).

Almost surely, 2^{130025425311053} is an apocalyptic number.

It is an amenable number.

130025425311053 is a deficient number, since it is larger than the sum of its proper divisors (1).

130025425311053 is an equidigital number, since it uses as much as digits as its factorization.

130025425311053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 35.

Adding to 130025425311053 its reverse (350113524520031), we get a palindrome (480138949831084).

The spelling of 130025425311053 in words is "one hundred thirty trillion, twenty-five billion, four hundred twenty-five million, three hundred eleven thousand, fifty-three".