Base | Representation |
---|---|
bin | 11101100100001100001011… |
… | …111000000110101010100110 |
3 | 122001101210000120001102100212 |
4 | 131210030023320012222212 |
5 | 114020404111020040032 |
6 | 1140315035535535422 |
7 | 36250244616522536 |
oct | 3544141370065246 |
9 | 561353016042325 |
10 | 130030334143142 |
11 | 38482611815a14 |
12 | 127008bb98a572 |
13 | 5772a66c40b04 |
14 | 2417704b474c6 |
15 | 10075c26c7bb2 |
hex | 76430be06aa6 |
130030334143142 has 8 divisors (see below), whose sum is σ = 195193374987600. Its totient is φ = 64965875813944.
The previous prime is 130030334143141. The next prime is 130030334143187. The reversal of 130030334143142 is 241341433030031.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 130030334143099 and 130030334143108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130030334143141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24645625517 + ... + 24645630792.
It is an arithmetic number, because the mean of its divisors is an integer number (24399171873450).
Almost surely, 2130030334143142 is an apocalyptic number.
130030334143142 is a deficient number, since it is larger than the sum of its proper divisors (65163040844458).
130030334143142 is a wasteful number, since it uses less digits than its factorization.
130030334143142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49291257630.
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 130030334143142 its reverse (241341433030031), we get a palindrome (371371767173173).
The spelling of 130030334143142 in words is "one hundred thirty trillion, thirty billion, three hundred thirty-four million, one hundred forty-three thousand, one hundred forty-two".
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