Base | Representation |
---|---|
bin | 11101100100001100111011… |
… | …011100011100110100011110 |
3 | 122001101212002011201220212111 |
4 | 131210030323130130310132 |
5 | 114020412224320401342 |
6 | 1140315251045024234 |
7 | 36250303450064551 |
oct | 3544147334346436 |
9 | 561355064656774 |
10 | 130031132200222 |
11 | 3848299124a020 |
12 | 12700aa30b507a |
13 | 5772b63393536 |
14 | 241777cb28698 |
15 | 100761c7b9217 |
hex | 76433b71cd1e |
130031132200222 has 8 divisors (see below), whose sum is σ = 212778216327672. Its totient is φ = 59105060091000.
The previous prime is 130031132200213. The next prime is 130031132200279. The reversal of 130031132200222 is 222002231130031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×1300311322002222 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (22), and also a Moran number because the ratio is a prime number: 5910506009101 = 130031132200222 / (1 + 3 + 0 + 0 + 3 + 1 + 1 + 3 + 2 + 2 + 0 + 0 + 2 + 2 + 2).
It is a junction number, because it is equal to n+sod(n) for n = 130031132200193 and 130031132200202.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2955253004529 + ... + 2955253004572.
It is an arithmetic number, because the mean of its divisors is an integer number (26597277040959).
Almost surely, 2130031132200222 is an apocalyptic number.
130031132200222 is a deficient number, since it is larger than the sum of its proper divisors (82747084127450).
130031132200222 is a wasteful number, since it uses less digits than its factorization.
130031132200222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5910506009114.
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 130031132200222 its reverse (222002231130031), we get a palindrome (352033363330253).
It can be divided in two parts, 1300311 and 32200222, that added together give a palindrome (33500533).
The spelling of 130031132200222 in words is "one hundred thirty trillion, thirty-one billion, one hundred thirty-two million, two hundred thousand, two hundred twenty-two".
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