Base | Representation |
---|---|
bin | 111100100011001111… |
… | …0000111101111001101 |
3 | 110102122002212110121022 |
4 | 1321012132013233031 |
5 | 4112301004220023 |
6 | 135422514243525 |
7 | 12252203661230 |
oct | 1710636075715 |
9 | 412562773538 |
10 | 130031320013 |
11 | 50167321341 |
12 | 2124b2865a5 |
13 | c35351c59a |
14 | 64176dd417 |
15 | 35b099d7c8 |
hex | 1e46787bcd |
130031320013 has 8 divisors (see below), whose sum is σ = 148610904960. Its totient is φ = 111452655600.
The previous prime is 130031319997. The next prime is 130031320021. The reversal of 130031320013 is 310023130031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130031320013 - 24 = 130031319997 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130031319973 and 130031320000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130031325013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 105128 + ... + 520686.
It is an arithmetic number, because the mean of its divisors is an integer number (18576363120).
Almost surely, 2130031320013 is an apocalyptic number.
It is an amenable number.
130031320013 is a deficient number, since it is larger than the sum of its proper divisors (18579584947).
130031320013 is an equidigital number, since it uses as much as digits as its factorization.
130031320013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 460267.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 130031320013 its reverse (310023130031), we get a palindrome (440054450044).
The spelling of 130031320013 in words is "one hundred thirty billion, thirty-one million, three hundred twenty thousand, thirteen".
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