Base | Representation |
---|---|
bin | 11000001110000110… |
… | …00001000110010111 |
3 | 1020120012200121120221 |
4 | 30013003001012113 |
5 | 203112300231320 |
6 | 5550142135211 |
7 | 640141544503 |
oct | 140703010627 |
9 | 36505617527 |
10 | 13003133335 |
11 | 5572a25595 |
12 | 262a881507 |
13 | 12c2c2ac4a |
14 | 8b4d43303 |
15 | 5118703aa |
hex | 3070c1197 |
13003133335 has 8 divisors (see below), whose sum is σ = 15604564176. Its totient is φ = 10401970560.
The previous prime is 13003133321. The next prime is 13003133347. The reversal of 13003133335 is 53333130031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13003133335 - 27 = 13003133207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62440 + ... + 172930.
It is an arithmetic number, because the mean of its divisors is an integer number (1950570522).
Almost surely, 213003133335 is an apocalyptic number.
13003133335 is a deficient number, since it is larger than the sum of its proper divisors (2601430841).
13003133335 is a wasteful number, since it uses less digits than its factorization.
13003133335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134033.
The product of its (nonzero) digits is 3645, while the sum is 25.
Adding to 13003133335 its reverse (53333130031), we get a palindrome (66336263366).
The spelling of 13003133335 in words is "thirteen billion, three million, one hundred thirty-three thousand, three hundred thirty-five".
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