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13003140030341 = 31419456130011
BaseRepresentation
bin1011110100111000011110…
…0010101101111110000101
31201001002101012000121010112
42331032013202231332011
53201020412321432331
643353320550202405
72511305634411656
oct275160742557605
951032335017115
1013003140030341
114163667612a9a
121560119353405
1373426338aa36
1432d4d907d52d
1517839518b32b
hexbd3878adf85

13003140030341 has 4 divisors (see below), whose sum is σ = 13422596160384. Its totient is φ = 12583683900300.

The previous prime is 13003140030329. The next prime is 13003140030379. The reversal of 13003140030341 is 14303004130031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13003140030341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13003140030301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209728064975 + ... + 209728065036.

It is an arithmetic number, because the mean of its divisors is an integer number (3355649040096).

Almost surely, 213003140030341 is an apocalyptic number.

It is an amenable number.

13003140030341 is a deficient number, since it is larger than the sum of its proper divisors (419456130043).

13003140030341 is an equidigital number, since it uses as much as digits as its factorization.

13003140030341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 419456130042.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13003140030341 its reverse (14303004130031), we get a palindrome (27306144160372).

The spelling of 13003140030341 in words is "thirteen trillion, three billion, one hundred forty million, thirty thousand, three hundred forty-one".

Divisors: 1 31 419456130011 13003140030341