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13003169141 is a prime number
BaseRepresentation
bin11000001110000110…
…01001110101110101
31020120012202102201002
430013003021311311
5203112302403031
65550143013045
7640142054054
oct140703116565
936505672632
1013003169141
115572a4a486
12262a89a185
1312c2c41331
148b4d5239b
1551187accb
hex3070c9d75

13003169141 has 2 divisors, whose sum is σ = 13003169142. Its totient is φ = 13003169140.

The previous prime is 13003169107. The next prime is 13003169167. The reversal of 13003169141 is 14196130031.

13003169141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11600367025 + 1402802116 = 107705^2 + 37454^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13003169141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13003169171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501584570 + 6501584571.

It is an arithmetic number, because the mean of its divisors is an integer number (6501584571).

Almost surely, 213003169141 is an apocalyptic number.

It is an amenable number.

13003169141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13003169141 is an equidigital number, since it uses as much as digits as its factorization.

13003169141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 29.

Adding to 13003169141 its reverse (14196130031), we get a palindrome (27199299172).

The spelling of 13003169141 in words is "thirteen billion, three million, one hundred sixty-nine thousand, one hundred forty-one".