Base | Representation |
---|---|
bin | 11101100100001101110101… |
… | …110110100001010111010111 |
3 | 122001101221121110121122122110 |
4 | 131210031311312201113113 |
5 | 114020421231200104421 |
6 | 1140315532212002103 |
7 | 36250336646154465 |
oct | 3544156566412727 |
9 | 561357543548573 |
10 | 130032112113111 |
11 | 384833443a308a |
12 | 12701117300333 |
13 | 5772c8b3b9750 |
14 | 2417832d27835 |
15 | 100767882da76 |
hex | 764375da15d7 |
130032112113111 has 32 divisors (see below), whose sum is σ = 189501361504000. Its totient is φ = 78824676420864.
The previous prime is 130032112113097. The next prime is 130032112113151. The reversal of 130032112113111 is 111311211230031.
It is not a de Polignac number, because 130032112113111 - 26 = 130032112113047 is a prime.
It is a super-3 number, since 3×1300321121131113 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130032112113151) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 395974515 + ... + 396302763.
It is an arithmetic number, because the mean of its divisors is an integer number (5921917547000).
Almost surely, 2130032112113111 is an apocalyptic number.
130032112113111 is a deficient number, since it is larger than the sum of its proper divisors (59469249390889).
130032112113111 is a wasteful number, since it uses less digits than its factorization.
130032112113111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 479935.
The product of its (nonzero) digits is 108, while the sum is 21.
Adding to 130032112113111 its reverse (111311211230031), we get a palindrome (241343323343142).
The spelling of 130032112113111 in words is "one hundred thirty trillion, thirty-two billion, one hundred twelve million, one hundred thirteen thousand, one hundred eleven".
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