Base | Representation |
---|---|
bin | 111100100011010000… |
… | …1100011011110000101 |
3 | 110102122011120012012112 |
4 | 1321012201203132011 |
5 | 4112301222020122 |
6 | 135422545430405 |
7 | 12252214430216 |
oct | 1710641433605 |
9 | 412564505175 |
10 | 130032220037 |
11 | 50167886565 |
12 | 2124b63b405 |
13 | c353776145 |
14 | 641789540d |
15 | 35b0aca2e2 |
hex | 1e46863785 |
130032220037 has 2 divisors, whose sum is σ = 130032220038. Its totient is φ = 130032220036.
The previous prime is 130032219953. The next prime is 130032220061. The reversal of 130032220037 is 730022230031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 109375056961 + 20657163076 = 330719^2 + 143726^2 .
It is a cyclic number.
It is not a de Polignac number, because 130032220037 - 216 = 130032154501 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130032219994 and 130032220021.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130032220337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016110018 + 65016110019.
It is an arithmetic number, because the mean of its divisors is an integer number (65016110019).
Almost surely, 2130032220037 is an apocalyptic number.
It is an amenable number.
130032220037 is a deficient number, since it is larger than the sum of its proper divisors (1).
130032220037 is an equidigital number, since it uses as much as digits as its factorization.
130032220037 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 23.
Adding to 130032220037 its reverse (730022230031), we get a palindrome (860054450068).
The spelling of 130032220037 in words is "one hundred thirty billion, thirty-two million, two hundred twenty thousand, thirty-seven".
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