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130032240421 is a prime number
BaseRepresentation
bin111100100011010000…
…1101000011100100101
3110102122011121020011111
41321012201220130211
54112301223143141
6135422550105021
712252214543516
oct1710641503445
9412564536144
10130032240421
115016789a906
122124b64b171
13c3537824c5
14641789ca0d
1535b0ad1381
hex1e46868725

130032240421 has 2 divisors, whose sum is σ = 130032240422. Its totient is φ = 130032240420.

The previous prime is 130032240407. The next prime is 130032240427. The reversal of 130032240421 is 124042230031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119792824321 + 10239416100 = 346111^2 + 101190^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130032240421 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130032240392 and 130032240401.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130032240427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65016120210 + 65016120211.

It is an arithmetic number, because the mean of its divisors is an integer number (65016120211).

Almost surely, 2130032240421 is an apocalyptic number.

It is an amenable number.

130032240421 is a deficient number, since it is larger than the sum of its proper divisors (1).

130032240421 is an equidigital number, since it uses as much as digits as its factorization.

130032240421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 130032240421 its reverse (124042230031), we get a palindrome (254074470452).

The spelling of 130032240421 in words is "one hundred thirty billion, thirty-two million, two hundred forty thousand, four hundred twenty-one".