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1300330220040 = 2333511319355207
BaseRepresentation
bin10010111011000001101…
…110001000101000001000
311121022101020201100222000
4102323001232020220020
5132301034014020130
62433210301231000
7162642252334125
oct22730156105010
94538336640860
101300330220040
11461515567415
12190019b62460
139580b646407
1446d1738774c
1523c57e03260
hex12ec1b88a08

1300330220040 has 256 divisors, whose sum is σ = 4395528460800. Its totient is φ = 341899149312.

The previous prime is 1300330220003. The next prime is 1300330220041. The reversal of 1300330220040 is 400220330031.

1300330220040 is a `hidden beast` number, since 1 + 300 + 3 + 302 + 20 + 0 + 40 = 666.

It is a super-2 number, since 2×13003302200402 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1300330219995 and 1300330220022.

It is not an unprimeable number, because it can be changed into a prime (1300330220041) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 23526117 + ... + 23581323.

It is an arithmetic number, because the mean of its divisors is an integer number (17170033050).

Almost surely, 21300330220040 is an apocalyptic number.

1300330220040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300330220040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2197764230400).

1300330220040 is an abundant number, since it is smaller than the sum of its proper divisors (3095198240760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300330220040 is a wasteful number, since it uses less digits than its factorization.

1300330220040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55533 (or 55523 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 18.

Adding to 1300330220040 its reverse (400220330031), we get a palindrome (1700550550071).

The spelling of 1300330220040 in words is "one trillion, three hundred billion, three hundred thirty million, two hundred twenty thousand, forty".